(2-y)^2+y^2+4(2-y)-8y=108

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Solution for (2-y)^2+y^2+4(2-y)-8y=108 equation:



(2-y)^2+y^2+4(2-y)-8y=108
We move all terms to the left:
(2-y)^2+y^2+4(2-y)-8y-(108)=0
We add all the numbers together, and all the variables
y^2+(-1y+2)^2+4(-1y+2)-8y-108=0
We add all the numbers together, and all the variables
y^2-8y+(-1y+2)^2+4(-1y+2)-108=0
We multiply parentheses
y^2-8y+(-1y+2)^2-4y+8-108=0
We add all the numbers together, and all the variables
y^2-12y+(-1y+2)^2-100=0
We move all terms containing y to the left, all other terms to the right
y^2-12y+(-1y+2)^2=100

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